5 2025-01-03  Freitag Abend
Sepp Wandling - Christine Burkert
   

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Paar: 5    Sepp Wandling - Christine Burkert

Score: 60,0    50,000 %    Platz: 4    
                      
Rnd  Tisch  Als  Geg  Board  Kont     Aus  Ergebnis  Score    %    Runde    %     Ges        %        Name d. Gegners

 1     2    N-S   2     19   3N  S +2 T2    460        1,0   25                                       Kirner - Steiner
                        20   2P  O -1 KA    100        2,0   50                                             
                        21   4P  S +1 K3    650        4,0  100                                             
                        22   3N  O -1 K6    100        4,0  100                                             
                        23   2T  W +2 K3       -130    1,0   25                                             
                        24   4H  N -1 T8        -50    0,0    0     12,0   50    12,0   50,000              

 2     3    N-S   4     13   2P  O -1 T4    100        1,0   25                                       Mocza - Obojes
                        14   2P  W -3 H7    150        3,0   75                                             
                        15   3N  O -1 P2     50        2,0   50                                             
                        16   3P  S  = H4    140        1,0   25                                             
                        17   2P  N  = T2    110        2,0   50                                             
                        18                       A=    2,0   50     11,0   46    23,0   47,917              

 3     3    O-W   1     7    3P  S +2 T9    200        4,0  100                                       Thorpe - Kurtovic
                        8    6P  N  = K10   980        0,0    0                                             
                        9    3N  W  = P10      -600    3,0   75                                             
                        10   3N  O -1 K2    100        1,0   25                                             
                        11   3N  N  = TD    400        3,0   75                                             
                        12   3N  S -1 P2       -100    3,0   75     14,0   58    37,0   51,389              

 4     2    O-W   3     1    2K  O -1 K3     50        0,0    0                                       Schindler - Wagner-Lothaller
                        2    2P  N +2 TA    170        3,0   75                                             
                        3    4H  N +1 K3    450        3,0   75                                             
                        4    2N  N +1 H3    150        2,0   50                                             
                        5    2P  N -2 HK       -200    3,0   75                                             
                        6    2T  W  = P3        -90    3,0   75     14,0   58    51,0   53,125              

 5     1    O-W   6     25   2T  N -2 K10      -100    2,0   50                                       Schwab - Ohrner
                        26   2T  W +3 H5       -150    0,0    0                                             
                        27   4P  S -1 KK        -50    2,0   50                                             
                        28   2P  O  = K3       -110    1,0   25                                             
                        29   4H  N -1 PK       -100    4,0  100                                             
                        30   5T  S +1 HA    420        0,0    0      9,0   38    60,0   50,000              


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