3 2025-03-31  Montag Abend
Christian Engblom - Kaija Ryömä
   

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Paar: 3    Christian Engblom - Kaija Ryömä

Score: 76    35,185 %    Platz: 10    
                         
Rnd  Tisch  Als  Geg  Board  Kont     Aus  Ergebnis  Score    %    Runde   %    Ges       %        Name d. Gegners

 1     2    O-W   6     4    2N  W  = H9       -120      6   75                                    Streicher - Pölzlbauer
                        5    2P  W -1 T5     50          6   75                                             
                        6    5Px O -1 H10   200          0    0       12  50     12  50,000                 

 2     4    N-S   5     25   4P  O +2 HA       -680      2   25                                    Thorpe - Kurtovic
                        26   2P  N -1 KA       -100      2   25                                             
                        27   4Kx O -2 TA    300          8  100       12  50     24  50,000                 

 3     1    O-W   10    7    3H  N +1 PB    170          0    0                                    Rathammer - Zeugner
                        8    4H  N  = KA    420          0    0                                             
                        9    5H  O -1 K6    100          0    0        0   0     24  33,333                 

 4     3    N-S   8     16   5K  N  = P2    400          0    0                                    Zhou - Winkler
                        17   5Hx S -4 KK       -800      0    0                                             
                        18   2P  O +2 TA       -170      3   38        3  13     27  28,125                 

 5     5    N-S   2     10   6T  S -4 HA       -400      0    0                                    Galabov - Genowitz
                        11   4H  W -2 PA    100          6   75                                             
                        12   4Px O -1 KD    100          8  100       14  58     41  34,167                 

 6     5    O-W   4     13   3T  O -1 H2    100          8  100                                    Wasserburger - Kadlec
                        14   3N  N +1 T4    430          0    0                                             
                        15   4H  O +1 PA       -450      7   88       15  63     56  38,889                 

 7     2    N-S   9     22   3H  N +1 K2    170          1   13                                    Bichlmaier - Hölbfer
                        23   4P  O  = K5       -620      0    0                                             
                        24   3N  N  = TA    400          5   63        6  25     62  36,905                 

 8     3    O-W   7     1    4H  N -1 PA        -50      6   75                                    Nieminen - Silen
                        2    2P  W  = T9       -110      0    0                                             
                        3    3K  O -5 TA    500          0    0        6  25     68  35,417                 

 9     4    O-W   1     19   5T  O -1 P2    100          0    0                                    Wohlfahrt - Mayerhofer-Schöpf
                        20   3H  O +1 T9       -170      4   50                                             
                        21   2P  W -1 TA     50          4   50        8  33     76  35,185                 


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