7 2025-07-10  Donnerstag Nachmittag
Alexander Haltrich - Gerhard Mocza
   

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Paar: 7    Alexander Haltrich - Gerhard Mocza

Score: 114    42,222 %    Platz: 11    
                     
Rnd  Tisch  Als  Geg  Board  Kont     Aus  Ergebnis  Score    %    Runde    %    Ges        %        Name d. Gegners

 1     4    N-S   3     10   3T  O  = K4       -110      4   40                                      Machu - Freissmuth
                        11   5K  W +1 H6       -420      6   60                                             
                        12   3K  W -1 TB     50          5   50       15   50     15   50,000               

 2     5    N-S   1     16   4H  W +2 KK       -680      2   20                                      Hensler - Stalzer
                        17   3K  W -2 P4    100          1   10                                             
                        18   4P  O -1 HA     50          1   10        4   13     19   31,667               

 3     3    O-W   11    13   5H  S +1 P10   680          1   10                                      Haberbauer - Paprsek
                        14   3P  O  = TA       -140      7   70                                             
                        15   5T  O -1 PK     50          3   30       11   37     30   33,333               

 4     6    O-W   5     25   2H  W -3 PA    300         10  100                                      Koril - Singer
                        26   3N  W -4 K4    400          1   10                                             
                        27   5H  N +2 P2    510          5   50       16   53     46   38,333               

 5     4    O-W   2     22   4H  O -1 PA    100          2   20                                      Pichler - Bachmaier
                        23   3P  N -1 H4       -100      6   60                                             
                        24   6Px N -2 HB       -300     10  100       18   60     64   42,667               

 6     6    N-S   9     4    4Hx S -3 TK       -800      0    0                                      Winkler - Ringdorfer
                        5    5T  N -1 HA       -100      0    0                                             
                        6    2N  W +1 K2       -150      4   40        4   13     68   37,778               

 7     1    O-W   10    19   3N  N +2 K2    460          1   10                                      Egerer - Neumayr
                        20   2H  W +2 T8       -170      8   80                                             
                        21   1N  S  = HK     90          2   20       11   37     79   37,619               

 8     5    O-W   4     7    2P  S  = HA    110          5   50                                      Scheiner - Ossmann
                        8    2K  S +1 PK    110          3   30                                             
                        9    4P  O  = KD       -620      9   90       17   57     96   40,000               

 9     2    N-S   12    1    6P  N  = H3    980          9   90                                      Zeugner - Schwetz
                        2    4P  W +1 KA       -450      3   30                                             
                        3    3N  S  = H9    400          6   60       18   60    114   42,222               


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