3 2025-08-08  Freitag Abend
Christine Burkert - Sepp Wandling
   

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Paar: 3    Christine Burkert - Sepp Wandling

Score: 55    45,833 %    Platz: 4    
                        
Rnd  Tisch  Als  Geg  Board  Kont     Aus  Ergebnis  Score    %    Runde    %    Ges        %        Name d. Gegners

 1     3    O-W   4     7    1N  S  = HA     90          0    0                                      Seibl-Kraus - Winkler
                        8    2P  O +4 K10      -230      2   50                                             
                        9    5Tx S -2 H4       -300      2   50                                             
                        10   4P  N  = HD    620          0    0                                             
                        11   4P  S  = TB    420          0    0                                             
                        12   2H  O +1 T2       -140      4  100        8   33      8   33,333               

 2     2    O-W   1     19   2K  N +1 TA    110          4  100                                      Pichler - Streicher
                        20   4H  N +1 P8    650          2   50                                             
                        21   3N  N -1 P2       -100      1   25                                             
                        22   4P  S +2 T5    480          4  100                                             
                        23   2P  N  = HB    110          4  100                                             
                        24   3N  S  = K2    400          0    0       15   63     23   47,917               

 3     1    O-W   6     13   2P  S -1 H4       -100      2   50                                      Aschauer - Schwab
                        14   1N  N  = PD     90          0    0                                             
                        15   2H  N +1 KA    140          0    0                                             
                        16   3P  S -2 H6       -100      3   75                                             
                        17   3N  N  = H2    400          1   25                                             
                        18   3K  N +2 PA    150          4  100       10   42     33   45,833               

 4     2    N-S   5     1    2P  N -1 HA        -50      0    0                                      Koblmüller - Lindner
                        2    3H  S +2 K2    200          4  100                                             
                        3    4H  W +1 KA       -650      2   50                                             
                        4    4P  W +1 H4       -650      3   75                                             
                        5    4H  W +1 P5       -450      0    0                                             
                        6    3N  W -1 T2    100          4  100       13   54     46   47,917               

 5     3    N-S   2     25   2H  O +3 PA       -200      4  100                                      Samek - Schauberger
                        26   2N  O  = H10      -120      1   25                                             
                        27   4P  S -1 T5        -50      0    0                                             
                        28   6N  N  = H10  1440          4  100                                             
                        29   4H  W -1 T6    100          0    0                                             
                        30   4H  S  = T5    420          0    0        9   38     55   45,833               


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