3 2025-12-06  Adventturnier
Elfriede Hiesleitner - Elisabeth Hensler
   

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Paar: 3    Elfriede Hiesleitner - Elisabeth Hensler

Score: 405,0 *    50,000 %    Platz: 14    
           
Rnd  Tisch  Als  Geg  Board  Kont      Aus  Ergebnis  Score    %    Runde   %      Ges       %        Name d. Gegners

 1    A 3   N-S   13    7    3T   W +1 HK       -130   18,0   60                                      Belin - Köpplinger
                        8    3Hx  S  = PA    530       30,0  100                                            
                        9    4P   W  = H3       -620    5,0   17     53,0  59     53,0  58,889              

 2    A 3   N-S   12    10   2P   W -1 HA    100       16,0   53                                      Stigleitner - Simkovics
                        11   4P   O -3 T9    150       30,0  100                                            
                        12   4P   W -1 H2     50        9,0   30     55,0  61    108,0  60,000              

 3    A 3   N-S   --    13                     Pause   15,0   50                                      Pause 
                        14                     Pause   15,0   50                                            
                        15                     Pause   15,0   50     45,0  50    153,0  56,667              

 4    A 3   N-S   19    16   4H   O -2 K4    200       30,0  100                                      Faymann - Illner
                        17   1N   N -3 KK       -150    5,0   17                                            
                        18   2P   N +3 H4    200       28,0   93     63,0  70    216,0  60,000              

 5    A 3   N-S   18    19   3K   N  = H6    110       17,0   57                                      Sova - Sova
                        20   3P   N  = HA    140       20,0   67                                            
                        21   3T   S  = KB    110       26,0   87     63,0  70    279,0  62,000              

 6    A 3   N-S   17    22   4Px  N -2 TB       -300    1,0    3                                      Kurtovic - Odelga
                        23   2N   W +1 H7       -150    6,0   20                                            
                        24   4P   W -2 P4    100       21,0   70     28,0  31    307,0  56,852              

 7    A 3   O-W   16    25   3Px  N -3 TK       -500   10,0   33                                      Grubhofer - Kubicek
                        26   3N   S  = TD    600        1,0    3                                            
                        27   3Kx  S -1 H5       -100   20,0   67     31,0  34    338,0  53,651              

 8    A 3   O-W   15    1    3P   S +1 HA    170        0,0    0                                      Jürss - Finz
                        2    3N   O -1 P3     50        4,0   13                                            
                        3    3N   W -1 H5    100        7,0   23     11,0  12    349,0  48,472              

 9    A 3   O-W   14    4    4T   O  = PA       -130   24,0   80                                      Schneider - Springer
                        5    5K   W -2 HK    100        4,0   13                                            
                        6    4Px  S -2 TA       -300   28,0   93     56,0  62    405,0  50,000              


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