5 2025-12-18  Donnerstag Nachmittag "Tassilo Cup"
Karlheinz Korbel - Franz Györög
   

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Paar: 5    Karlheinz Korbel - Franz Györög

Score: 142,0    37,566 %    Platz: 15    
                      
Rnd  Tisch  Als  Geg  Board  Kont      Aus  Ergebnis  Score    %    Runde    %      Ges        %        Name d. Gegners

 1     5    N-S   15    13   1N   O +2 H2       -150    9,0   64                                        Kirner - Steiner
                        14   1N   N +1 K5    120       10,0   71                                            
                        15   3K   O -1 T2     50        8,0   57     27,0   64     27,0   64,286            

 2     5    N-S   14    16   4H   N -1 T3        -50    3,0   21                                        Griesmayr - Bachmaier
                        17   1N   O  = P2        -90    0,0    0                                            
                        18   3K   S +2 T4    150       12,0   86     15,0   36     42,0   50,000            

 3     5    N-S   13    19   4K   W  = P9       -130    7,0   50                                        Thorpe - Della Lucia
                        20   2T   N -1 HD       -100    4,0   29                                            
                        21   2H   O +1 K3       -140    0,0    0     11,0   26     53,0   42,063            

 4     5    N-S   12    22   2P   O  = T2       -110    2,0   14                                        Stadler - Winter
                        23   4H   O +1 T9       -650    1,0    7                                            
                        24   2P   W +1 TA       -140    4,0   29      7,0   17     60,0   35,714            

 5     5    N-S   11    25   3T   N -1 KD        -50    7,0   50                                        Singer - Koril
                        26   4P   S  = TK    620        9,0   64                                            
                        27   2N   W  = P2       -120    6,0   43     22,0   52     82,0   39,048            

 6     5    N-S   19    1    2K   O  = P2        -90    7,0   50                                        Scheiner - Rojahn
                        2    1H   O +2 P7       -140    6,0   43                                            
                        3    3P   O +1 HB       -170    9,0   64     22,0   52    104,0   41,270            

 7     5    O-W   18    4    3H   O -1 P9    100        0,0    0                                        Kadlec - Kampel
                        5    6K   N  = P9   1370        4,0   29                                            
                        6    2P   N -1 TA        -50    2,0   14      6,0   14    110,0   37,415            

 8     5    O-W   17    7    3N   W +3 P9       -690    9,0   64                                        Rezek - Wagner-Lothaller
                        8    3N   O +1 H4       -430   10,0   71                                            
                        9    3P   W -2 H8    200        2,0   14     21,0   50    131,0   38,988            

 9     5    O-W   16    10   2P   N +1 H3    140        2,0   14                                        Frei - Zimmermann
                        11   4H   O -1 TB     50        1,0    7                                            
                        12   Pass              0        8,0   57     11,0   26    142,0   37,566            


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